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純粋・応用数学・数学隣接分野(含むガロア理論)20 (1002レス)
純粋・応用数学・数学隣接分野(含むガロア理論)20 http://rio2016.5ch.net/test/read.cgi/math/1745503590/
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852: 現代数学の系譜 雑談 ◆yH25M02vWFhP [] 2025/07/10(木) 07:08:02.22 ID:J4CWtGen >>848-851 ふっふ、ほっほ もう詰んだのか?w ;p) >>727より再録 >”∩{x⊂A|{}∈x∧∀y[y∈x→y∪{y}∈x]}” この式は、下記(ja.ipedia)のペアノの公理 自然数の集合論的構成 の式だが 上記の通り、∩のIterated binary operation の意味が不明確(この説明を求められると詰まるだろう) なので、∩を使わない 別の工夫がある(下記) 例えば en.wikipedia Axiom of infinity, Extracting the natural numbers from the infinite set, Alternative method あるいは fr.wikipedia Axiome de l'infini あるいは、>>569 筑波大 坪井明人 PDF P9 https://www.math.tsukuba.ac.jp/~tsuboi/und/14logic3.pdf 数理論理学II あるいは、>>677 渕野昌 P10(無限公理)https://fuchino.ddo.jp/books/intro-to-set-theory-and-constructibility.pdf 「ゲーデルと20世紀の論理学第4巻」(東京大学出版会,2007)の,渕野 昌の執筆した第I部 以上 (引用終り) 繰り返すが、∩のIterated binary operation の意味が不明確 さらに、wikipedia Axiom of infinity 記述を引用する >>630-631 より https://en.wikipedia.org/wiki/Axiom_of_infinity Axiom of infinity Extracting the natural numbers from the infinite set The infinite set I is a superset of the natural numbers. To show that the natural numbers themselves constitute a set, the axiom schema of specification can be applied to remove unwanted elements, leaving the set N of all natural numbers. This set is unique by the axiom of extensionality. To extract the natural numbers, we need a definition of which sets are natural numbers. The natural numbers can be defined in a way that does not assume any axioms except the axiom of extensionality and the axiom of induction—a natural number is either zero or a successor and each of its elements is either zero or a successor of another of its elements. In formal language, the definition says: ∀n(n∈N⟺([n=∅∨∃k(n=k∪{k})]∧∀m∈n[m=∅∨∃k∈n(m=k∪{k})])). Or, even more formally: ∀n(n∈N⟺([∀k(¬k∈n)∨∃k∀j(j∈n⟺(j∈k∨j=k))]∧ ∀m(m∈n⇒[∀k(¬k∈m)∨∃k(k∈n∧∀j(j∈m⟺(j∈k∨j=k)))]))). つづく http://rio2016.5ch.net/test/read.cgi/math/1745503590/852
854: 132人目の素数さん [] 2025/07/10(木) 07:12:32.45 ID:e06yId8e >>852 >∩のIterated binary operation の意味が不明確 まだ言ってて草 >(この説明を求められると詰まるだろう) だから >一般の集合族の共通部分の定義 (x∈∩M)⇔(∀A∈M, x∈A) と何度言わせるんだ? 言葉が分からないのか? なら小学校の国語からやり直し http://rio2016.5ch.net/test/read.cgi/math/1745503590/854
867: 現代数学の系譜 雑談 ◆yH25M02vWFhP [] 2025/07/10(木) 10:20:18.09 ID:CJHicHXJ >>854-866 ふっふ、ほっほ ぐだぐだ 無駄な多弁を弄するね ;p) さて >>852-853より https://en.wikipedia.org/wiki/Axiom_of_infinity Axiom of infinity Extracting the natural numbers from the infinite set Φ(x) be the formula that says "x is inductive"; i.e. Φ(x)=(∅∈x∧∀y(y∈x→(y∪{y}∈x))). Informally, what we will do is take the intersection of all inductive sets. More formally, we wish to prove the existence of a unique set W such that ∀x(x∈W↔∀I(Φ(I)→x∈I)). (*) For existence, we will use the Axiom of Infinity combined with the Axiom schema of specification. Let I be an inductive set guaranteed by the Axiom of Infinity. Then we use the axiom schema of specification to define our set W={x∈I:∀J(Φ(J)→x∈J)} – i.e. W is the set of all elements of I, which also happen to be elements of every other inductive set. This clearly satisfies the hypothesis of (*), since if x∈W, then x is in every inductive set, and if x is in every inductive set, it is in particular in I, so it must also be in W. For uniqueness, first note that any set that satisfies (*) is itself inductive, since 0 is in all inductive sets, and if an element x is in all inductive sets, then by the inductive property so is its successor. Thus if there were another set W′ that satisfied (*) we would have that W′⊆W since W is inductive, and W⊆W′since W′is inductive. Thus W=W′. Let ω denote this unique element. This definition is convenient because the principle of induction immediately follows: If I⊆ω is inductive, then also ω⊆I, so that I=ω.■ (引用終り) これで尽きている 1)”Informally, what we will do is take the intersection of all inductive sets.” intersection:共通部分 英: intersection(下記)ね 2)で、これ ”Informally”とあるよね。つまり、 ”∩{x⊂A|{}∈x∧∀y[y∈x→y∪{y}∈x]}”>>727 は、”Informally”なんだよ ここを勘違いした人が ja.wikipediaに >>847の”ペアノの公理”を 書いたんじゃないの? 3)さて、Formallyには ”Let I be an inductive set guaranteed by the Axiom of Infinity. Then we use the axiom schema of specification to define our set W={x∈I:∀J(Φ(J)→x∈J)} – i.e. W is the set of all elements of I, which also happen to be elements of every other inductive set.” だよね。ここに、”∩”は 使われない 詰んだな (参考) https://ja.wikipedia.org/wiki/%E5%85%B1%E9%80%9A%E9%83%A8%E5%88%86_(%E6%95%B0%E5%AD%A6) 共通部分( 英: intersection, meet)とは、与えられた集合の集まり(族)全てに共通に含まれる元を全て含み、それ以外の元は含まない集合のことである http://rio2016.5ch.net/test/read.cgi/math/1745503590/867
920: 現代数学の系譜 雑談 ◆yH25M02vWFhP [] 2025/07/19(土) 15:34:03.80 ID:jT6bEcWg >>874 戻る >Informally と intersection が同一文内にある。だから∩を使った構成は間違い。 えーと >>867 より再録 >>852-853より https://en.wikipedia.org/wiki/Axiom_of_infinity Axiom of infinity Extracting the natural numbers from the infinite set Φ(x) be the formula that says "x is inductive"; i.e. Φ(x)=(∅∈x∧∀y(y∈x→(y∪{y}∈x))). Informally, what we will do is take the intersection of all inductive sets. More formally, we wish to prove the existence of a unique set W such that ∀x(x∈W↔∀I(Φ(I)→x∈I)). (*) For existence, we will use the Axiom of Infinity combined with the Axiom schema of specification. Let I be an inductive set guaranteed by the Axiom of Infinity. Then we use the axiom schema of specification to define our set W={x∈I:∀J(Φ(J)→x∈J)} – i.e. W is the set of all elements of I, which also happen to be elements of every other inductive set. This clearly satisfies the hypothesis of (*), since if x∈W, then x is in every inductive set, and if x is in every inductive set, it is in particular in I, so it must also be in W. For uniqueness, first note that any set that satisfies (*) is itself inductive, since 0 is in all inductive sets, and if an element x is in all inductive sets, then by the inductive property so is its successor. Thus if there were another set W′ that satisfied (*) we would have that W′⊆W since W is inductive, and W⊆W′since W′is inductive. Thus W=W′. Let ω denote this unique element. This definition is convenient because the principle of induction immediately follows: If I⊆ω is inductive, then also ω⊆I, so that I=ω.■ (引用終り) 1)”Informally, what we will do is take the intersection of all inductive sets.” intersection:共通部分 英: intersection(下記)ね 2)で、これ ”Informally”とあるよね。つまり、 ”∩{x⊂A|{}∈x∧∀y[y∈x→y∪{y}∈x]}”>>727 は、”Informally”なんだよ ここを勘違いした人が ja.wikipediaに >>847の”ペアノの公理”を 書いたんじゃないの? 3)さて、Formallyには ”Let I be an inductive set guaranteed by the Axiom of Infinity. Then we use the axiom schema of specification to define our set W={x∈I:∀J(Φ(J)→x∈J)} – i.e. W is the set of all elements of I, which also happen to be elements of every other inductive set.” だよね。ここに、”∩”は 使われない (引用終り) つづく http://rio2016.5ch.net/test/read.cgi/math/1745503590/920
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