[過去ログ] 純粋・応用数学(含むガロア理論)8 (942レス)
前次1-
抽出解除 レス栞

このスレッドは過去ログ倉庫に格納されています。
次スレ検索 歴削→次スレ 栞削→次スレ 過去ログメニュー
809
(1): 現代数学の系譜 雑談 ◆yH25M02vWFhP 2021/06/04(金)23:24 ID:mqX8IzZM(9/12) AAS
>>808
つづき

外部リンク:en.wikipedia.org
4 Sets versus classes
Sets versus classes
Certain mathematical "relations", such as "equal to", "subset of", and "member of", cannot be understood to be binary relations as defined above, because their domains and codomains cannot be taken to be sets in the usual systems of axiomatic set theory. For example, if we try to model the general concept of "equality" as a binary relation =, we must take the domain and codomain to be the "class of all sets", which is not a set in the usual set theory.

In most mathematical contexts, references to the relations of equality, membership and subset are harmless because they can be understood implicitly to be restricted to some set in the context. The usual work-around to this problem is to select a "large enough" set A, that contains all the objects of interest, and work with the restriction =A instead of =. Similarly, the "subset of" relation ⊆ needs to be restricted to have domain and codomain P(A) (the power set of a specific set A): the resulting set relation can be denoted by ⊆A. Also, the "member of" relation needs to be restricted to have domain A and codomain P(A) to obtain a binary relation ∈A that is a set. Bertrand Russell has shown that assuming ∈ to be defined over all sets leads to a contradiction in naive set theory.

つづく
810: 現代数学の系譜 雑談 ◆yH25M02vWFhP 2021/06/04(金)23:25 ID:mqX8IzZM(10/12) AAS
>>809
つづき

Another solution to this problem is to use a set theory with proper classes, such as NBG or Morse?Kelley set theory, and allow the domain and codomain (and so the graph) to be proper classes: in such a theory, equality, membership, and subset are binary relations without special comment. (A minor modification needs to be made to the concept of the ordered triple (X, Y, G), as normally a proper class cannot be a member of an ordered tuple; or of course one can identify the binary relation with its graph in this context.)[20] With this definition one can for instance define a binary relation over every set and its power set.
(引用終り)
以上
前次1-
スレ情報 赤レス抽出 画像レス抽出 歴の未読スレ AAサムネイル

ぬこの手 ぬこTOP 0.050s