素数の規則を見つけたい。。。 (701ﾚｽ)
上下前次1-新
抽出解除 必死ﾁｪｯｶｰ(本家) (べ) 自ID ﾚｽ栞 あぼーん
ﾘﾛｰﾄﾞ規制です｡10分ほどで解除するので､他のﾌﾞﾗｳｻﾞへ避難してください｡
203: 2023/12/03(日)00:59 ID:ytu0Oj+u(1/9) AAS
cos(2pi*((n1/2+1)/2^n+(n2/3+1)/3^n+(n3/5+1)/5^n+(n4/7+1)/7^n)) > cos(2pi*(11^2/(2*3*5*7)^n))
これを満たす整数n,n1,n2,n3,n4が存在するとき
e^(i*2pi*((n1/2+1)/2^n+(n2/3+1)/3^n+(n3/5+1)/5^n+(n4/7+1)/7^n))=e^(i*2pi*(X/(2*3*5*7)^n))
のXが素数になる
204: 2023/12/03(日)01:11 ID:ytu0Oj+u(2/9) AAS
cos(2pi*((n1/2+1)/2^n+(n2/3+1)/3^n+(n3/5+1)/5^n+(n4/7+1)/7^n)) > cos(2pi*(11^2/(2*3*5*7)^(n+1)))
これを満たす整数n,n1,n2,n3,n4が存在するとき
e^(i*2pi*((n1/2+1)/2^n+(n2/3+1)/3^n+(n3/5+1)/5^n+(n4/7+1)/7^n))=e^(i*2pi*(X/(2*3*5*7)^(n+1)))
のXが素数になる
cos(2pi*((1/2+1)/2^2+(2/3+1)/3^2+(a/5+1)/5^2+(b/7+1)/7^2)) > cos(2pi*(11^2/(2*3*5*7)^3))
a = 125 n_1 + 19, b = 343 n_2 + 78, n_1 element Z, n_2 element Z
e^(i*2pi*((1/2+1)/2^2+(2/3+1)/3^2+(19/5+1)/5^2+(78/7+1)/7^2))=e^(-(13 i π)/4630500)
205: 2023/12/03(日)01:14 ID:ytu0Oj+u(3/9) AAS
cos(2pi*((1/2+1)/2^2+(2/3+1)/3^2+(a/5+1)/5^2+(b/7+1)/7^2+(c/11+1)/11^2)) > cos(2pi*(13^2/(2*3*5*7*11)^3))
a = 125 n_1 + 29, b = 343 n_2 + 82, c = 1331 n_3 + 1198, n_1 element Z, n_2 element Z, n_3 element Z
e^(i*2pi*((1/2+1)/2^2+(2/3+1)/3^2+(29/5+1)/5^2+(82/7+1)/7^2+(1198/11+1)/11^2))=e^(-(23 i π)/6163195500)
206: 2023/12/03(日)01:48 ID:ytu0Oj+u(4/9) AAS
cos(2pi*((7/2+1)/2^3+(29/3+1)/3^3+(a/5+1)/5^3+(b/7+1)/7^3)) > cos(2pi*(11^2/(2*3*5*7)^4))
a = 625 n_1 + 204, b = 2401 n_2 + 1693, n_1 element Z, n_2 element Z
e^(i*2pi*((7/2+1)/2^3+(29/3+1)/3^3+(204/5+1)/5^3+(1693/7+1)/7^3)) =e^((89 i π)/972405000)
207: 2023/12/03(日)01:50 ID:ytu0Oj+u(5/9) AAS
cos(2pi*((5/2+1)/2^3+(29/3+1)/3^3+(a/5+1)/5^3+(b/7+1)/7^3)) > cos(2pi*(11^2/(2*3*5*7)^4))
a = 625 n_1 + 582, b = 2401 n_2 + 541, n_1 element Z, n_2 element Z
e^(i*2pi*((5/2+1)/2^3+(29/3+1)/3^3+(582/5+1)/5^3+(541/7+1)/7^3)) =e^(-(73 i π)/972405000)
208: 2023/12/03(日)13:26 ID:ytu0Oj+u(6/9) AAS
|L|=X+Y+Z=√((√x+√y+i*√z)*(√x-√y+i*√z)*(√x+√y-i*√z)*(√x-√y-i*√z))
|L|=X+Y+Z=√((√x+√y+i*√z)*(√x-√y+i*√z)*(√x+√y-i*√z)*(√x-√y-i*√z))
|L|=√(x^2+y^2+z^2+2*(x*y*cos(0)+x*z*cos(0)+y*z*cos(π)))
|L|=0
√x=√y+i*√z、-√y+i*√z、√y-i*√z、-√y-i*√z
|L|=X+Y+Z=√((√x+√y+i^2*√z)*(√x-√y+i^2*√z)*(√x+√y-i^2*√z)*(√x-√y-i^2*√z))
|L|=√(x^2+y^2+z^2+2*(x*y*cos(π)+x*z*cos(π)+y*z*cos(π)))
省6
209: 2023/12/03(日)16:41 ID:ytu0Oj+u(7/9) AAS
a^n+b^n≠c^n
1/a^n+1/b^n≠c^n/(ab)^n
cos(2pi*(1/a^n+1/b^n)) > cos(2pi*(c^n/(ab)^n))
cos(2pi*(1/2^3+1/(3*5)^3)) > cos(2pi*(c^3/(2*3*5)^3))
(-0.5 + 0.866025 i) (27000 n + 3383)^(1/3)<c<(-0.5 + 0.866025 i) (27000 n + 23617)^(1/3), n element Z
cos(2pi*(1/(2*7)^4+1/(3*5)^4)) > cos(2pi*(c^3/(2*3*5*7)^4))
(-0.5 + 0.866025 i) (1944810000 n + 89041)^(1/3)<c<(-0.5 + 0.866025 i) (1944810000 n + 1944720959)^(1/3), n element Z
210: 2023/12/03(日)19:40 ID:ytu0Oj+u(8/9) AAS
cos(2pi*(1/2^3+1/(3*5)^3)) =cos(2pi*(c^3/(2*3*5)^3))
c = 27000 n + 1127, n element Z
c = 27000 n + 7873, n element Z
c = 27000 n + 10127, n element Z
c = 27000 n + 19127, n element Z
c = 27000 n + 25873, n element Z
1127^3 mod 27000 =3383 =2^3+15^3
省4
211: 2023/12/03(日)19:56 ID:ytu0Oj+u(9/9) AAS
cos(2pi*(1/2^4+1/(3*5*7)^4)) =cos(2pi*(c^4/(2*3*5*7)^4))
c = 1944810000 n + 5250989, n element Z
c = 1944810000 n + 11474377, n element Z
c = 1944810000 n + 19508123, n element Z
c = 1944810000 n + 36233489, n element Z
c = 1944810000 n + 90568123, n element Z
c = 1944810000 n + 104825261, n element Z
省15
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