素数の規則を見つけたい。。。 (701レス)
素数の規則を見つけたい。。。 http://rio2016.5ch.net/test/read.cgi/math/1640355175/
上
下
前次
1-
新
通常表示
512バイト分割
レス栞
抽出解除
必死チェッカー(本家)
(べ)
自ID
レス栞
あぼーん
180: 132人目の素数さん [sage] 2023/09/17(日) 00:19:58.42 ID:NvL18fxN e^(2 i π (2/13(2/11 (2/7 (2/5 (n/3 + 1/2) + 1/2) + 1/2) + 1/2)+1/2)) cos(2 π (2/13(2/11 (2/7 (2/5 (n/3 + 1/2) + 1/2) + 1/2) + 1/2)+1/2)) < cos(2π*17^2/(2*3*5*7*11*13)) 1/16 (15015 m - 9101)<n<1/16 (15015 m - 8812) e^(2 i π (2/13(2/11 (2/7 (2/5 (-551/3 + 1/2) + 1/2) + 1/2) + 1/2)+1/2))=e^((281 i π)/15015) e^(2 i π (2/13(2/11 (2/7 (2/5 (-553/3 + 1/2) + 1/2) + 1/2) + 1/2)+1/2))=e^((217 i π)/15015) ←非素数 e^(2 i π (2/13(2/11 (2/7 (2/5 (-554/3 + 1/2) + 1/2) + 1/2) + 1/2)+1/2))=e^((185 i π)/15015) ←非素数 e^(2 i π (2/13(2/11 (2/7 (2/5 (-556/3 + 1/2) + 1/2) + 1/2) + 1/2)+1/2))=e^((121 i π)/15015) ←非素数 e^(2 i π (2/13(2/11 (2/7 (2/5 (-557/3 + 1/2) + 1/2) + 1/2) + 1/2)+1/2))=e^((89 i π)/15015) e^(2 i π (2/13(2/11 (2/7 (2/5 (-559/3 + 1/2) + 1/2) + 1/2) + 1/2)+1/2))=e^((25 i π)/15015) ←非素数 e^(2 i π (2/13(2/11 (2/7 (2/5 (-560/3 + 1/2) + 1/2) + 1/2) + 1/2)+1/2))=e^((-7 i π)/15015) e^(2 i π (2/13(2/11 (2/7 (2/5 (-562/3 + 1/2) + 1/2) + 1/2) + 1/2)+1/2))=e^((-71 i π)/15015) e^(2 i π (2/13(2/11 (2/7 (2/5 (-563/3 + 1/2) + 1/2) + 1/2) + 1/2)+1/2))=e^((-103 i π)/15015) e^(2 i π (2/13(2/11 (2/7 (2/5 (-565/3 + 1/2) + 1/2) + 1/2) + 1/2)+1/2))=e^((-167 i π)/15015) e^(2 i π (2/13(2/11 (2/7 (2/5 (-566/3 + 1/2) + 1/2) + 1/2) + 1/2)+1/2))=e^((-199 i π)/15015) e^(2 i π (2/13(2/11 (2/7 (2/5 (-568/3 + 1/2) + 1/2) + 1/2) + 1/2)+1/2))=e^((-263 i π)/15015) http://rio2016.5ch.net/test/read.cgi/math/1640355175/180
181: 132人目の素数さん [sage] 2023/09/17(日) 00:45:26.83 ID:NvL18fxN e^(2 i π (2/17(2/13(2/11 (2/7 (2/5 (n/3 + 1/2) + 1/2) + 1/2) + 1/2)+1/2)+1/2)) cos(2 π (2/17(2/13(2/11 (2/7 (2/5 (n/3 + 1/2) + 1/2) + 1/2) + 1/2)+1/2)+1/2)) >cos(2π*19^2/(210*11*13*17)) 1/32 (255255 m - 145721)<n<5/32 (51051 m - 29072) e^(2 i π (2/17(2/13(2/11 (2/7 (2/5 (3433/3 + 1/2) + 1/2) + 1/2) + 1/2)+1/2)+1/2))=e^((283 i π)/255255) e^(2 i π (2/17(2/13(2/11 (2/7 (2/5 (-4546/3 + 1/2) + 1/2) + 1/2) + 1/2)+1/2)+1/2))=e^((137 i π)/255255) e^(2 i π (2/17(2/13(2/11 (2/7 (2/5 (3430/3 + 1/2) + 1/2) + 1/2) + 1/2)+1/2)+1/2))=e^((91 i π)/255255) e^(2 i π (2/17(2/13(2/11 (2/7 (2/5 (-4547/3 + 1/2) + 1/2) + 1/2) + 1/2)+1/2)+1/2))=e^((73 i π)/255255) e^(2 i π (2/17(2/13(2/11 (2/7 (2/5 (3428/3 + 1/2) + 1/2) + 1/2) + 1/2)+1/2)+1/2))=e^((-37 i π)/255255) e^(2 i π (2/17(2/13(2/11 (2/7 (2/5 (3427/3 + 1/2) + 1/2) + 1/2) + 1/2)+1/2)+1/2))=e^((-101 i π)/255255) e^(2 i π (2/17(2/13(2/11 (2/7 (2/5 (3425/3 + 1/2) + 1/2) + 1/2) + 1/2)+1/2)+1/2))=e^((-229 i π)/255255) http://rio2016.5ch.net/test/read.cgi/math/1640355175/181
182: 132人目の素数さん [sage] 2023/09/17(日) 00:49:51.30 ID:NvL18fxN 連続する素数の差分は2^nと2^(n-1)が交互に来る 73 +2^4=89 89+2^3=97 97+2^4=113 http://rio2016.5ch.net/test/read.cgi/math/1640355175/182
メモ帳
(0/65535文字)
上
下
前次
1-
新
書
関
写
板
覧
索
設
栞
歴
スレ情報
赤レス抽出
画像レス抽出
歴の未読スレ
AAサムネイル
Google検索
Wikipedia
ぬこの手
ぬこTOP
1.317s*