素数の規則を見つけたい。。。

素数の規則を見つけたい。。。 (701ﾚｽ)
上下前次 1-新
通常表示 512ﾊﾞｲﾄ分割ﾚｽ栞

179: １３２人目の素数さん [sage] 2023/09/16(土) 23:51:32.96 ID:PJtUNqdO

e^(i*2pi*(1/2+(1/2+((1/2+(1/2+n/3)*(2*3)/(3*5))*(2*3*5))/(3*5*7))*(2*3*5*7)/(3*5*7*11)))
1/8 (1155 m - 809)<n<5/8 (231 m - 128)を満たしかつ3の倍数でないとき分子が素数（非素数が混じる

e^(i*2pi*(1/2+(1/2+((1/2+(1/2-82/3)*(2*3)/(3*5))*(2*3*5))/(3*5*7))*(2*3*5*7)/(3*5*7*11))) =e^((137 i π)/1155)
e^(i*2pi*(1/2+(1/2+((1/2+(1/2-83/3)*(2*3)/(3*5))*(2*3*5))/(3*5*7))*(2*3*5*7)/(3*5*7*11))) =e^((121 i π)/1155)　←非素数
e^(i*2pi*(1/2+(1/2+((1/2+(1/2-85/3)*(2*3)/(3*5))*(2*3*5))/(3*5*7))*(2*3*5*7)/(3*5*7*11))) =e^((89 i π)/1155)
e^(i*2pi*(1/2+(1/2+((1/2+(1/2-86/3)*(2*3)/(3*5))*(2*3*5))/(3*5*7))*(2*3*5*7)/(3*5*7*11))) =e^((73 i π)/1155)
e^(i*2pi*(1/2+(1/2+((1/2+(1/2-88/3)*(2*3)/(3*5))*(2*3*5))/(3*5*7))*(2*3*5*7)/(3*5*7*11))) =e^((41 i π)/1155)
e^(i*2pi*(1/2+(1/2+((1/2+(1/2-89/3)*(2*3)/(3*5))*(2*3*5))/(3*5*7))*(2*3*5*7)/(3*5*7*11))) =e^((25 i π)/1155)　←非素数
e^(i*2pi*(1/2+(1/2+((1/2+(1/2-91/3)*(2*3)/(3*5))*(2*3*5))/(3*5*7))*(2*3*5*7)/(3*5*7*11))) =e^((-7 i π)/1155)
e^(i*2pi*(1/2+(1/2+((1/2+(1/2-92/3)*(2*3)/(3*5))*(2*3*5))/(3*5*7))*(2*3*5*7)/(3*5*7*11))) =e^((-23 i π)/1155)
e^(i*2pi*(1/2+(1/2+((1/2+(1/2-94/3)*(2*3)/(3*5))*(2*3*5))/(3*5*7))*(2*3*5*7)/(3*5*7*11))) =e^((-55 i π)/1155)
e^(i*2pi*(1/2+(1/2+((1/2+(1/2-95/3)*(2*3)/(3*5))*(2*3*5))/(3*5*7))*(2*3*5*7)/(3*5*7*11))) =e^((-71 i π)/1155)
e^(i*2pi*(1/2+(1/2+((1/2+(1/2-97/3)*(2*3)/(3*5))*(2*3*5))/(3*5*7))*(2*3*5*7)/(3*5*7*11))) =e^((-103 i π)/1155)
e^(i*2pi*(1/2+(1/2+((1/2+(1/2-98/3)*(2*3)/(3*5))*(2*3*5))/(3*5*7))*(2*3*5*7)/(3*5*7*11))) =e^((-119 i π)/1155) ←非素数
e^(i*2pi*(1/2+(1/2+((1/2+(1/2-100/3)*(2*3)/(3*5))*(2*3*5))/(3*5*7))*(2*3*5*7)/(3*5*7*11)))=e^((-151 i π)/1155)
e^(i*2pi*(1/2+(1/2+((1/2+(1/2-101/3)*(2*3)/(3*5))*(2*3*5))/(3*5*7))*(2*3*5*7)/(3*5*7*11)))=e^((-167 i π)/1155)

http://rio2016.5ch.net/test/read.cgi/math/1640355175/179

上下前次 1-新書関写板覧索設栞歴

あと 522 ﾚｽあります
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