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(ˆø—pŠJŽn)
https://en.wikipedia.org/wiki/Well-order
Well-order
Examples and counterexamples
Reals
The standard ordering … of any real interval is not a well ordering, since, for example, the open interval (0, 1) º [0,1] does not contain a least element.
From the ZFC axioms of set theory (including the axiom of choice) one can show that there is a well order of the reals.
Nonetheless, it is possible to show that the ZFC+GCH axioms alone are not sufficient to prove the existence of a definable (by a formula) well order of the reals.[1]
However it is consistent with ZFC that a definable well ordering of the reals exists-for example, it is consistent with ZFC that V=L, and it follows from ZFC+V=L that a particular formula well orders the reals, or indeed any set.
È14
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>>128
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Thus, from 4.9 (ii) we obtain: it is consistent with Z-F, AC and GCH,that there is no set-theoretically definable well-ordering of the continuum.
(That is, it is consistent to adjoin to these axioms the statement, foreach formula ? of L with two free variables, which expresses that Fdoes not determine a well-ordering of the continuum.)
This bears onquestions dealt with by Myhill and Scott [13] (1).
(*). The following result of Scott, which will appear in that paper, is of specialinterest in this connection: it is provable in Z-F that there is a definable well-orderingA with field I a subset of the continuum, such that any other well-ordering 4, of thissort has field TiCr.
A simple explicit definition of this A can be given.
(ˆø—pI‚è)
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134
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>>132
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>>128 •â‘«
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http://paiotunoowari.hatenadiary.jp/entry/2015/12/03/133610
®—ñ‰Â”\’è— 2015-12-03 ‚Ï‚¢‚¨‚“ú‹L
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